3/x-3 —2/x-2=1/x-1方程有意义,则x≠3,x≠2,x≠13/x-3 —1/x-1=2/x-2{ 3(x-1) - (x-3) }/{(x-1)(x-3)} = 2/(x-2)2x /{(x-1)(x-3)} = 2/(x-2)x /{(x-1)(x-3)} = 1/(x-2)x(x-2) = (x-1)(x-3)x^2-2x = x^2-4x+32x=3x=3...