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1/x(1/sinx–1/x)的极限
人气:226 ℃ 时间:2020-06-10 09:14:33
解答
lim 1/x*(1/sin x-1/x)变化得:=lim (x-sin x)/(sin x*x^2) (sin x 与 x 是等价无穷小)=lim (x-sin x)/(x^3) (属于0/0型,可用洛必塔)=lim (1-cos x)/(3x^2) =lim 2(sin x/2)^2/(3x^2) (sin x/2 与 x/2 是等价无...
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