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当x=(-1\2)²时,y是方程(2y+3)²=(2y+1)(2y-1)的根.
求多项式x²-6xy+9y²-x+3y-2
人气:228 ℃ 时间:2020-06-03 02:50:07
解答
(2y+3)²=(2y+1)(2y-1)
4y²+12y+9=4y²-1
12y=-10
y=-5/6
x=(-1/2)²=1/4
x²-6xy+9y²-x+3y-2
=(x-3y)²-(x-3y)-2
=(x-3y+1)(x-3y-2)
=(1/4-3*(-5/6)+1)(1/4-3*(-5/6)-2)
=(15/4)(3/4)
=45/16
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