f(x)=sinx-√3cosx+1
=2sin(x-π/3)+1
1.2kπ-π/2<=x-π/3<=2kπ+π/2
2kπ-π/6<=x<=2kπ+5π/6增区间 【2kπ-π/6,2kπ+5π/6】
减区间【2kπ+π/6,2kπ+11π/6】 k∈Z
2.0<=x<=π
-π/3<=x-π/3<=2π/3
-√3/2<=sin(x-π/3)<=1
最大值=2 x=5π/6
最小值=-√3/2x=0f(x)=sin(π-x)+√3cos(π+x)+1不是sinx-√3cosx+1啊诱导公式sin(π-x)=sinxcos(π+x)=-cosx哦~明白了，忘记诱导公式了，谢谢~