2/3[3/2(x-4)-6]=2x+1去分母：2[3/2(x-4)-6]=3(2x+1)去分母：3(x-4)-12=3(2x+1)去括号：3x-12-12=6x+3移项得：3x-6x=3+12+12合并得：-3x=27化为系数1：x=-92/3[3/2(x-4)-6]=2x+1去分母：(x-4)-4=2x+1去括号：x-4-4=2...