则二氧化碳的物质的量为
0.44g |
44g/mol |
其分子数为0.01mol×NA=0.01×6.02×1023=6.02×1021,
故答案为:0.01mol;6.02×1021;
②设样品中Na2CO3为xmol,则
Na2CO3+H2SO4→Na2SO4+CO2↑+H2O
1 1
x 0.01mol
1 |
1 |
x |
0.01mol |
解得x=0.01mol,
则m (Na2CO3)=0.01mol×106g/mol=1.06g,
NaOH的质量分数为
(5−1.06)g |
5g |
答:样品中Na2CO3的质量是1.06g,NaOH的质量分数是78.8%.