若方程组4x+3y=11 kx+(k-1)y=3的解x是y的两倍,则k的值为 快
人气:489 ℃ 时间:2019-08-20 21:44:26
解答
依据题意,x=2y,代入方程组得:
4*2y+3y=11
k*2y+(k-1)y=3
所以:
11y=11
(2k+k-1)y=3
所以:
y=1
(3k-1)*1=3
所以:3k-1=3
所以:k=4/3
答:k的值为4/3
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