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数学
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因式分解:a^2b^2c-ab^3c+a^2bc^2-ab^2c^2
人气:199 ℃ 时间:2020-04-02 23:34:58
解答
a^2b^2c-ab^3c+a^2bc^2-ab^2c^2
=abc(ab-b^2+ac-bc)
=abc(a-b)(b+c)
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