P+CuSO4+H2O=Cu3P+H2So4+H2Po4 生成1molCU3P时,参加反应的P的物质的量
用得失电子守恒来做
人气：170 ℃ 时间：2020-01-16 15:04:56
解答
22P+30CuSO4+66H2O=10Cu3P+30H2So4+12H3Po4
10p+30e=10p3-
30cu2++30e=30cu+
12p-60e=12p5+
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