我来试试吧...设n^2+n+11=m²4n^2+4n+44=(2n+1)²+43=(2m)²(2m)²-(2n+1)²=[2m-2n-1][2m+2n+1]=43=1*4343是质数,分解只有1*43一种故2m-2n-1=12m+2n+1=43 解得 n=10故仅当n=10,n^2+n+11为完全...