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分解因式10(x-y)²-5x(y-x)
人气:169 ℃ 时间:2020-05-19 05:20:49
解答
(10x-10y)(x-y)+5x(x-y)=(10x-10y+5x)(x-y)=(15x-10y)(x-y)=15x^2-25xy+10y^2那把(y-x)变成(x-y)行不行(y-x)=-(x-y)我算了不对哪里不对,请指正。(15x-10y)(x-y)=5(x-y)(3x-2y)。y-x=-(x-y)而不是y-x=x-y。把(y-x)变成(x-y)之后得5﹙x-2y﹚﹙x-y﹚你要考虑正负号的变化啊,你不能傻傻的前面是负号你变号之后还是负号,你要明白负负得正,原先5x前的负号要变成正号。10(x-y)²那要变他怎么算啊-10(y-x)10(x-y)²=10(x-y)(x-y)=(10x-10y)(x-y).-5x(y-x)=5x(x-y)........这里有正负号的转变,看仔细了然后两式提取公因式,就得(10x-10y+5x)(x-y)-10﹙y-x﹚﹙y-x﹚-5x﹙y-x﹚=麻烦你了哦10(x-y)²=10(x-y)(x-y)=10[-(y-x)][-(y-x)]=10(y-x)(y-x),变形过程中有两个负号了,所以还是正号。
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