求函数y=(3-sinx)/(2-cosx)的值域
y=(3-sinx)/(2-cosx)变为
sinx-ycosx=3-2y再用辅助角公式接下去怎么做
人气:148 ℃ 时间:2019-12-06 02:42:59
解答
sinx-ycosx=3-2y变为3-2y=sinx-ycosx=√ (1+y²)[√ 1/(1+y²)]sinx-[y/√ (1+y²)]cosx=√ (1+y²)sin(x- α) —— sinα=y/√ (1+y²),cosα=√ 1/(1+y²)因为 |sin(x- α)|=...
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