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一题初一的因式分解
(x-2y)x^3-(y-2x)y^3
人气:169 ℃ 时间:2020-02-04 19:17:11
解答
(x-2y)x^3-(y-2x)y^3
=(x^4-2x^3y-y^4+2xy^3)
=[x^2+y^2][x^2-y^2]-2xy[x^2-y^2]
=[x^2-y^2][x^2+y^2-2xy]
=[x+y][x-y][x-y]^2
=[x+y][x-y]^3
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