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复数1-i/(1+i)2的虚部
人气:225 ℃ 时间:2020-06-28 05:34:21
解答
(1-i)/(1+i)²
=(1-i)/(1+2i-1)
=(1-i)/(2i)
=(1-i)i/(-2)
=(i+1)/(-2)
=(-1/2) +(-1/2)i
虚部:-1/2
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