3Cl2+8NH3=6NH4Cl+N2 当有160.5gNH4Cl产生时,求氧化的氨气是多少克?
人气:322 ℃ 时间:2020-02-03 08:13:52
解答
8个NH3中即有8个N;8个N中有6个未参加氧化还原反应(价态不变,NH3和NH4Cl中N都为-3价),另两个被氧化(由NH3中的-3价变成N2中的0价,升3价)因此即有2个NH3被氧化,6个NH3未被氧化3Cl2+8NH3=6NH4Cl+N2X 160.5g136g 321...
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