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化简求值:1/2x^2y^3*(-3xy^2)+(-2xy)^2*xy^3+(1/4y)^2·(2xy)^3,其中x=1,y=-1
人气:333 ℃ 时间:2019-08-20 20:37:39
解答
1/2x^2y^3*(-3xy^2)+(-2xy)^2*xy^3+(1/4y)^2·(2xy)^3
= -3/2 x^3 y^5 + 4x^3 y^5 + 1/2 x^3 y^5 = 2 x^3 y^5 = 2(xy)^3 * y^2 = -2好像是-3吧?= -3/2 x^3 y^5 + 4x^3 y^5 + 1/2 x^3 y^5 = 3 x^3 y^5 = 3(xy)^3 * y^2 = -3
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