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数学
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lim x→0[ln(cosx)]/x^2
人气:217 ℃ 时间:2020-04-07 00:42:56
解答
答:
属于0-0型,应用洛必达法则:
lim(x→0) [ln(cosx)]/x^2
=lim(x→0) [(1/cosx)*(-sinx)]/(2x)
=lim(x→0) -sinx/(2x)
=-1/2
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