(3a的平方b)的平方+8a的6次方b的平方÷(-2a的平方b)
人气:209 ℃ 时间:2019-08-20 12:14:14
解答
^表示次方
(3a的平方b)的平方+8a的6次方b的平方÷(-2a的平方b)
=(3a^2b)^2+8a^6b^2÷(-2a^2b)
=9a^4b^2-(8÷2)a^(6-2)b^(2-1)
=9a^4b^2-4a^4b
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