某有机物只含CHO三种元素,它的相对分子质量为88,元素质量分数为碳占68.2%,氢占13.6%,
N(C)=88*68.2%/12=5.
N(H)=88*13.6%/1=12
N(O)=88*(1-68.2%-13.6%)/16=1
求该有机物的分子式C5H12O