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数学
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因式分解x² 2xy-3y ² 3x y 2
人气:123 ℃ 时间:2019-12-11 19:50:11
解答
1 3
1 -1
x² +2xy-3y ²+3x+ y+ 2
=(x+3y)(x-y)+3x+y+2
x+3y 2
x-y 1
=(x+3y+2)(x-y+1)请重打一遍,没看懂,谢了。(x² +2xy-3y ²)+3x+ y+ 2
【十字相乘法】
13
1-1
=(x+3y)(x-y)+3x+y+2
【十字相乘法】
x+3y 2
x-y 1
=(x+3y+2)(x-y+1)
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