(1+2+...+n)分之1
=2/[n(n+1)]
=2*(1/n-1/(n+1))
1+(1+2)分之1+(1+2+3)分之1+.+(1+2+3+.10)分之1
=2*(1-1/2+1/2-1/3+...+1/10-1/11)
=2*(1-1/11)
=20/11