先化简,再求值!
4x²y-［6xy-3（4xy-2）-x²y］+1
＝4x²y-(6xy-12xy+6-x²y)+1
=5x²y+6xy-5
=xy(5x+6)-5
因为x=2,y=2分之1,所以：
4x²y-［6xy-3（4xy-2）-x²y］+1
＝2*2分之1*(5*2+6)-5
=16-5
=11