2(x²+y²)²-8xy(x²+y²)+8x²y²
=2[(x²+y²)²-2×2xy(x²+y²)+(2xy)²]
=2[(x²+y²)-2xy]²
=2(x²-2xy+y²)²
=2[(x-y)²]²
=2(x-y)的4次方
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