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求sin^2 40°+cos^2 10°-sin40°sin80°的值.
人气:403 ℃ 时间:2020-05-24 04:13:51
解答
用到积化和差公式和倍角公式sinαsinβ=-[cos(α+β)-cos(α-β)]/2cos^2 α=1/2(1+cos2α)sin^2 40°+cos^2 10°-sin40°sin80°=cos^2 50°+cos^2 10°+1/2[cos (40°+80°)-cos(40°-80°)=1/2(1+cos100°)+1/2(1...
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