是 7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3+3 吧?
合并后结果 = 3 ,与 x、y 取值无关.
他的说明是对的.确实有道理.这个算式能告诉我过程吗？7x^3-6x^3y+3x^2y+3x^3+6x^3y-3x^2y-10x^3+3

=(7x^3+3x^3-10x^3)+(-6x^3y+6x^3y)+(3x^2y-3x^2y)+3
=0+0+0+3
=3