将40g溶质质量分数为36.5%的盐酸稀释为溶质质量分数为10%的盐酸需要水的质量是多少
将40g溶质质量分数为36.5%的盐酸稀释为溶质质量分数为10%的盐酸,需要水的质量是多少?
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人气：114 ℃ 时间：2019-10-10 06:07:48
解答
需要水的质量是 x
40g*36.5%=(40g+x)*10%
x=106g
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