已知函数f（x）满足：f（1）=1/4,4f（x）f（y）=f（x+y）+f（x-y）（x、y属于R）,求f（2010）值._数学解答

已知函数f（x）满足：f（1）=1/4,4f（x）f（y）=f（x+y）+f（x-y）（x、y属于R）,求f（2010）值.

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解答

4 f (0) f (0) = 2 f (0)f (0) = 1/24 f (0) f (x) = f (x) + f (x) = 2 f (x)4 f (x) f (1) = f (x + 1) + f (x - 1)f (x + 1) = f (x) - f (x - 1)f (x) = f (x - 1) - f (x - 2)事实上可以求得通项公式(1/4)*(1/2...