求函数y=lg（tanx+1）+根号（4sin平方x-3）的定义域_数学解答

tanx+1>0
tanx>-1
所以kπ-π/44(sinx)^2-3>=0
(sinx)^2>=3/4
-1<=sinx<=-√3/2,√3/2<=sinx<=1
所以2kπ+4π/3<=x<=2kπ+5π/3
2kπ+π/3<=x<=2kπ+2π/3
即kπ+π/3<=x<=kπ+2π/3
所以是kπ+π/3<=x