求log以2为底cosπ/9的对数+log以2为底cos2π/9+log以2为底4π/9=
人气:301 ℃ 时间:2020-05-21 07:33:19
解答
同底的对数相加,结果等于真数积的对数
真数之积为
cosπ/9cos2π/9cos4π/9
=(8sinπ/9cosπ/9cos2π/9cos4π/9)/(8sinπ/9)
=4sin2π/9cos2π/9cos4π/9)/(8sinπ/9)
=(2sin4π/9cos4π/9)/(8sinπ/9)
=(sin8π/9)/(8sinπ/9)
=(sin(π-π/9))/(8sinπ/9)
=1/8
所以log2 (1/8)=-3,即原式=-3
推荐
- 若cosα=log以8为底2的对数,且α属于(0,π/2),则tan(π-α)的值
- 设a=3^0.5,b=log以3为底的2 c=cos2/3π,排列大小,
- 若α ,β为锐角,P=log以cosα为底(sin50°+sin40°)的对数,
- log以2为底5的对数等于多少?
- (1)已知sin(π-x)=log以8为底1/4的对数,且x∈(-π/2,0),则cos(π+x)的值?
- 余弦怎么转换成正弦
- 已知向量m(2sinx,cosx)向量n=(sinx,2sinx),f(x)=向量m×n
- 激发兴趣用英语怎么说
猜你喜欢