∵对数函数真数＞0
∴log(1/2){log3[log(0.2)^x}＞0
∴0＜log3[log(0.2)^x]＜1
∴1＜log(0.2)^x＜3
∴1/125＜x＜1/5即0.008＜x＜0.2