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lim→0+ lnx ln(1+X)
人气:218 ℃ 时间:2020-04-25 11:45:16
解答
lim→0+ lnx ln(1+X)=lim→0+ ln(1+X)/(1/inx) 运用洛比达法则=lim→0+ (1/x+1)/(-1/xln^2x)=lim→0+ 1/x+1 *lim→0+ -x*ln^2x=lim→0+ -ln^2x/(1/x) 运用洛比达法则=lim→0+ -(2lnx/x)/(-1/x^2) =lim→0+ 2lnx/(...
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