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(5x+m)方=25x方-10xy+n
m=_____ n=_______
人气:277 ℃ 时间:2020-05-24 02:57:34
解答
原式 (5x+m)^2 = 25x^2-10xy+n
左边平方得 25x^2+10mx+m^2 = 25x^2-10xy+n
根据等式两边各项应该对应相等
则有+10mx = -10xy
+m^2 = n
∴m = -y n = m^2 = y^2
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