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求(49又48/49)*98和(-105-5/6)*12的计算过程,
人气:356 ℃ 时间:2020-07-02 01:06:07
解答
(49又48/49)*98
=49*98+48*2
=49*98+98
=(49+1)*98
=50*98
=490
(-105-5/6)*12
=-105*12-10
=-1200-60-10
=-1270
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