已知log(1/7)[log(3)(log(2)x)]=0已知log1/7[log3(log2x)]=0(1/7;3;2都为底数)_数学解答

已知log(1/7)[log(3)(log(2)x)]=0
已知log1/7[log3(log2x)]=0(1/7;3;2都为底数),x^(-1/2)=

人气：247 ℃　时间：2020-02-03 13:44:00

解答

log1/7[log3(log2x)]=0=log1/7(1)
所以log3(log2x)=1
log3(log2x)=log3(3)
log2(x)=3
x=2³
x=8