记得才做过?√x=t dx=2tdt
∫(0,4) (2√x)/(2+√x )dx
=∫(0,2) (4t^2)/(2+t )dt
=4∫(0,2) (t-2+4/(2+t ))dt
=4[t^2/2-2t+4ln(2+t)]|(0,2)
=4(-2+8ln2-4ln2)
=8(2ln2-1)