初一绝对值练习题 .急
已知|ab-2|与|b-1|互为相反数
试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+...+1/(a+2009)(b+2009)
人气:352 ℃ 时间:2020-04-05 04:53:53
解答
因为:|ab-2|与|b-1|互为相反数∴ ab-2=0,b-1=0∴ a=2,b=11/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2008)(b+2008)=1/2*1+1/3*2+1/4*3+...+1/2010*2009=1-1/2+1/2-1/3+1/3-1/4+...+1/2009-1/2010=1-1/2010=2009/2010...
推荐
猜你喜欢
- happiness is for everyone.求译!
- 写小数时,整数部分仍按( )的写法,整数部分是0的要写( ).
- 《人民解放军百万大军横渡长江》一文是按什么顺序报道三路军的渡江作战的?为什么这样安排顺序?
- 屏风,纳凉,帷幕,缓冲,造型,伧俗、雅俗之别造句
- To turn your dream into reality,you should first ______the hard life here which you has not got used to so far
- 足球循环赛中,红队胜黄队,比分为4:1,黄队胜蓝队,比分为1:0,蓝队胜红队,比分为1:0,算各队的净胜球数.
- 2.2*(-2.1)+1.21*4.2-2.1*0.22简算!
- it took him three hours to clean his bedroom的同义句