| (a+b)2 |
| (a−b)2 |
| 2(a−b) |
| 3(a+b) |
| a2 |
| (a+b)(a−b) |
| b |
| a |
=
| 2(a+b) |
| 3(a−b) |
| ab |
| (a+b)(a−b) |
=
| 2(a+b)2−3ab |
| 3(a+b)(a−b) |
=
| 2a2+ab+2b2 |
| 3(a+b)(a−b) |
故答案为
| 2a2+ab+2b2 |
| 3(a+b)(a−b) |
| a+b |
| a−b |
| 2a−2b |
| 3a+3b |
| a2 |
| a2−b2 |
| a |
| b |
| (a+b)2 |
| (a−b)2 |
| 2(a−b) |
| 3(a+b) |
| a2 |
| (a+b)(a−b) |
| b |
| a |
| 2(a+b) |
| 3(a−b) |
| ab |
| (a+b)(a−b) |
| 2(a+b)2−3ab |
| 3(a+b)(a−b) |
| 2a2+ab+2b2 |
| 3(a+b)(a−b) |
| 2a2+ab+2b2 |
| 3(a+b)(a−b) |