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根号(1+2sin(π-2)cos(π+2)
人气:392 ℃ 时间:2019-11-19 02:53:41
解答
根号1+2sin(π-2)cos(π-2)
=根号(sin²(π-2)+cos²(π-2)+2sin(π-2)cos(π-2))
=根号(sin(π-2)+cos(π-2))²
=sin(π-2)+cos(π-2)
sin(π-2)+cos(π-2)
=sin2-cos2
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