1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99怎么求
人气:410 ℃ 时间:2020-03-23 20:06:49
解答
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99
=(2/3+2/8+2/15+2/24+2/35+2/48+2/63+2/80+2/99)÷2
=[ (3-1)/(3×1)+(4-2)/(4×2)+(5-3)/(5×3)+(6-4)/(6×4)
+(7-5)/(7×5)+(8-6)/(8×6)+(9-7)/(9×7)+(10-8)/(10×8)+(11-9)/(11×9) ]÷2
=(1-1/3+1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7+1/6-1/8+1/7-1/9+1/8-1/10+1/9-1/11)÷2
=(1+1/2-1/10-1/11)÷2
=36/55
推荐
- 若一组按规律排成的数为:3,8,-15,24,35,-48,63,80,-99……,则这组数的第3n+1项是
- ( ) 35 63 80 99 143 A:24 B:15 C:8 D:1 求该题解题方法,
- 1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80=?要简便算法啊,
- 1/3+1/15+1/35+1/63+1/99
- 1/3+1/8+1/15+1/24+1/35+...+1/80+1/99 怎么解
- 已知y=根号2x-3+根号3-2x+2,求2x+39y的平方根
- we have more rules-don't eat in class
- 家庭生活的400字小片段 .急!
猜你喜欢