ha:hb:hc=bc:ac:ab=2:x:4
设ha = 2u, hb = xu, hc = 4u
a = 2s/2u = 1/2 v,
b = 2s/xu=1/x v
c = 2s/4u = 1/4 v
a:b:c = 1/2: 1/x: 1/4
a:b:c = 4x a: 4x b :4x c =4x *1/2 : 4x *1/x : 4x * 1/4 = 2x : 4 : xa = 2s/2u = 1/2 v, b = 2s/xu=1/x vc = 2s/4u = 1/4 v不理解，我是初一，能用简单一点的吗a = 2s/2u =1/2 *[2s/u] b = 2s/xu = 1/x *[2s/u]c = 2s/4u = 1/4 *[2s/u] 把 2s/u看作一个整体 v所以说a = 2s/2u = 1/2 v, b = 2s/xu=1/x vc = 2s/4u = 1/4 v用在比例, 大家都含有这个整体v, 所以约掉了就得到 a:b:c = 1/2: 1/x: 1/4噢,v 就是 [2s/u] 这个缩写