方程x平方+y平方-x+y+k=0表示一个圆,则实数k取值范围是多少
人气:179 ℃ 时间:2020-03-26 19:37:55
解答
配方得:(x-1/2)^2+(y+1/2)^2=1/2-k
因此有:1/2-k>0
即:k
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