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z=sin(xy)+cos^2(xy)一阶偏导数
人气:441 ℃ 时间:2020-04-10 20:59:38
解答
∂Z/∂x= y*cos(xy) -2cos(xy)*sin(xy)*y
= y*cos(xy) - y*sin(2xy)
∂Z/∂y= x*cos(xy) -2cos(xy)*sin(xy)*x
= x*cos(xy) - x*sin(2xy)
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