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(a-a/a+1)÷(a的平方-2a)/(a的平方-4)×1/(a+2)
人气:125 ℃ 时间:2020-04-04 01:06:07
解答
原式=(a²+a-a)/(a+1)×(a²-4)/(a²-2a)×1/(a+2)
=a²/(a+1)×(a+2)(a-2)/a(a-2)×1/(a+2)
=a²/(a+1)×(a+2)/a×1/(a+2)
=a(a+2)/(a+1)×1/(a+2)
=a/(a+1)
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