∫(-π/2到π/2)(sin(x+π/6))/((sinx)^2)+1)dx
=∫(-π/2到π/2)(sinxcosπ/6+cosxsinπ/6))/((sinx)^2)+1)dx （第1部分是奇函数,积分=0)
=∫(-π/2到π/2)(sinπ/6))/((sinx)^2)+1)dsinx
=arctansinx |(-π/2到π/2)
=π/2恩，非常感谢，不过你的答案好像算错了，应该是π/4。但过程是对的。呵呵，sinπ/6掉了