二次根式的加减运算题
(1)根号3+根号2分之1+根号2+1分之1-根号3-1分之2=?(抱歉,实在不会打根号和分数线)
(2)加减求值:根号a分之2-根号2分之a=2a分之a的平方+4(在分数线上)+2(在根号内)+根号2a分之a方+4(在分数线上)-2(在根号内),其中a=2.
(3)设x,y是有理数,且x,y满足等式x平方+2y+根号2y(y在根号外面)=17-4倍根号2,求x-y的值.
注:第二题要先化简在求值.
人气:410 ℃ 时间:2020-02-20 14:56:59
解答
(1)√3+(1/√2)+√2+1/1-√3-2/1
= (√3-√3)+(1/√2)+√2+(1-2)
= 0+(1/√2)+√2-1
= (1/√2)+√2-1
= √2{(1/√2)[(1/√2)+√2]}-1
= √2[(1/√2)*(1/√2)+(1/√2)*√2]-1
= √2(1/2+1)-1
= (3√2)2-1
= (3√2-2)/2
(2)实在是读不懂题
(3)这题太繁琐了
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