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sin14/3π+cos(-23π/4)+tan(-25π/3)=?
人气:372 ℃ 时间:2020-06-07 14:55:45
解答
原式=sin(4π+2/3π)+cos(-6π+π/4)+tan(-8π-π/3)
=sin(2π/3)+cos(π/4)-tan(π/3)
=√3/2+√2/2-√3
=(-√3+√2)/2
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