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设y=y(x)由方程cos(x+y)+y=1确定,求dy/dx
人气:380 ℃ 时间:2020-03-17 03:55:37
解答
对两边求导:[-sin(x+y)](1+dy/dx)+dy/dx=0 -sin(x+y)-[sin(x+y)]dy/dx+dy/dx=0 dy/dx=[sin(x+y)]/[1-sin(x+y)]
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