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sin(-19π/6)= sin(-16π/3)= cos(-79π/6)=
人气:357 ℃ 时间:2020-01-29 07:40:57
解答
sin(-19π/6)= sin(-19π/6+4π)= sin(5π/6)=0.5

sin(-16π/3)= sin(-19π/3+6π)= sin(-π/3)=-√3/2

cos(-79π/6)=cos(-79π/6+14π)=cos(5π/6)=-√3/2
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