取10ML质量分数为98%的硫酸(密度为1.84g/cm3)可配制成9.8%的硫酸多少克?
人气：332 ℃ 时间：2019-08-22 15:42:12
解答
设可以配成9.8%的硫酸a克,根据纯硫酸的质量守恒,建立方程为：
10X1.84X98%=aX9.8%
解方程可得a=184克
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