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已知f(x)=sin(π/6-x)^2-cos(π/4+x)^2+cos(π/6)cos(π/6-2x)
化简f(x)
人气:448 ℃ 时间:2020-03-25 23:13:43
解答
(x)=sin(π/6-x)^2-cos(π/4+x)^2+cos(π/6)cos(π/6-2x)
=1/2-1/2cos(π/3-2x)-1/2-1/2cos(π/2+2x)+根号3/2cos(π/6-2x)
=-1/2cos(π/3-2x)+1/2sin2x+根号3/2cos(π/6-2x)
=-1/4cos2x-根号3/4sin2x+3/4cos2x+根号3/4sin2x+1/2sin2x
=1/2sin2x+1/2cos2x
=根号2/2sin(2x+π/4)
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